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63x^2-8x-2=3x+5
We move all terms to the left:
63x^2-8x-2-(3x+5)=0
We get rid of parentheses
63x^2-8x-3x-5-2=0
We add all the numbers together, and all the variables
63x^2-11x-7=0
a = 63; b = -11; c = -7;
Δ = b2-4ac
Δ = -112-4·63·(-7)
Δ = 1885
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{1885}}{2*63}=\frac{11-\sqrt{1885}}{126} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{1885}}{2*63}=\frac{11+\sqrt{1885}}{126} $
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